Shirt box, 12 x 9 x 2 in
- Input
- 24 x 17 x 3 cm | 12 x 9 x 2 in
- Expected output
- 48 x 40.5 cm | 25 x 20 in
The diagonal method asks for a 21 1/4 in square and the ribbon is about 65 in.
Carregando ferramenta… / Loading tool…
how much wrapping paper do i need
A 14 x 8 x 5 in shoe box takes a 29 x 28 in sheet with the standard method. The width is the wrap-around of the box plus the seam, and the length is the box length plus the height twice and the tuck at the ends. Below are the formula, the cube, cylinder and round-item cases and the ribbon.
The diagonal method asks for a 21 1/4 in square and the ribbon is about 65 in.
The 29 x 28 in matches the source example; the diagonal method asks for 28 3/8 in and the ribbon is about 79 in.
The cube is where the diagonal saves the most: 24 1/8 in on a side.
With the ends tied like a candy wrapper the length goes up to 23 in.
It is a square: gather the corners at the top and tie it with ribbon.
For a 14 x 8 x 5 in shoe box, a 29 x 28 in sheet with the standard method. The width is 2 x width + 2 x height + 3 in (16 + 10 + 3) and the length is length + 2 x height + 4 in (14 + 10 + 4). With the diagonal method a square 28 3/8 in on a side is enough, and it also covers the whole box.
The wrap is 2 x length + 2 x width + 4 x height, and the bow adds 12 to 18 inches. For a 14 x 8 x 5 in box the wrap is 28 + 16 + 20 = 64 in and with a 14.8 in bow the total is about 79 in. For a single band around the middle, the circumference is enough.
From 2 to 3 inches (5 to 7.6 cm); the standard formula uses 3 inches. The calculator lets you change that value under More options, and when in doubt the source says to add another inch.
You can, with a tight seam and folds. The calculator standard method is generous on purpose: a 3 inch seam and a 2 inch tuck per end. Cutting those down saves paper, but raises the risk of the seam opening or an end running short. The diagonal method is another route.
There is no formula; use the quick method. Lay the paper face down, center the gift, roll it, check the 2 to 3 inch overlap and that both ends pass the center, mark and cut. A cardboard box the size of the gift also solves it.
The source formula uses 3 in (7.6 cm) and the quick method says 2 to 3 in.
28 3/8 in x 28 3/8 in
Diagonal method, 5.56 sq ft of paper.
Rule: side = square root of 2 x (longest edge + shortest edge + 1 in allowance), with the box turned 45 degrees (How to Wrap a Present, NRICH, University of Cambridge).
29 in x 28 in
Needs a roll at least 28 in wide.
28 3/8 in x 28 3/8 in
Needs a roll at least 28 3/8 in wide.
Uses 1% less paper than the standard method.
78 7/8 in
From 75 7/8 in to 81 3/4 in, depending on the bow size.
Rule: 2 x length + 2 x width + 4 x height + a 12 to 18 in bow.
The gift sits at 45 degrees in the center of the square sheet and the four corners fold to the middle of the lid.