10th term
- Input
- a₁=3, d=4
- Expected output
- a₁₀ = 39
3 + 9×4.
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arithmetic progression
In an AP, the difference between consecutive terms is constant (the common difference d).
3 + 9×4.
10·(3 + 39) ÷ 2.
In an AP we add a constant difference to each term (linear growth). In a GP we multiply by a constant ratio (exponential growth). AP: 2, 5, 8, 11… (d = 3). GP: 2, 6, 18, 54… (r = 3).
In an AP we add the ratio; in a GP we multiply. AP grows linearly, GP exponentially.
Subtract a term from the next: d = a₂ − a₁.
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