Vertical and horizontal asymptotes
- Input
- (2x + 1)/(x - 3)
- Expected output
- x = 3; y = 2; f(-0.5) = 0
Vertical x = 3; horizontal y = 2; root -0.5. Equal degrees: 2/1.
rational function asymptotes graph
Type a fraction of polynomials, for example (2x + 1)/(x - 3). The tool draws each branch of the curve without connecting the two sides of the asymptote, dashes the asymptotic lines and lists the verticals, the horizontal or oblique one, the holes and the roots in the panel.
Vertical x = 3; horizontal y = 2; root -0.5. Equal degrees: 2/1.
Vertical x = 0; horizontal y = 0; no root; odd function. Numerator degree is lower.
Hole at (1, 2); root -1; no vertical asymptote. The factor (x - 1) cancels.
Vertical x = 0; oblique y = x; local maximum (-1, -2) and local minimum (1, 2). Numerator of degree 2, denominator of degree 1.
Verticals x = -2 and x = 2; horizontal y = 0; root 0. x² - 4 = (x - 2)(x + 2).
Vertical x = 0; horizontal y = 0; always positive. Both branches go up.
Type the function, for example x^2 - 4x + 3. The parabola opens upward if a is positive and downward if it is negative. The vertex is at x = -b/2a: here x = 2 and y = -1. The roots come from (-b ± √Δ)/2a with Δ = b² - 4ac = 4, so x = 1 and x = 3, and the parabola crosses the y axis at c = 3. The tool marks all of these points and shows their exact form.
It can. The horizontal asymptote describes the behavior for very large x and does not stop the curve from crossing it earlier. The function x/(x² - 4) has asymptote y = 0 and passes through (0, 0). A vertical asymptote is never crossed, because the function is not defined at that x.
Substitute the root into the numerator. If the numerator is not zero, it is a vertical asymptote. If it is also zero and the factor cancels, it is a hole. In (x² - 1)/(x - 1) the numerator is 0 at x = 1, and after canceling you get x + 1, with a hole at (1, 2). The tool does this check using the multiplicity of the roots.
Divide the numerator by the denominator; the linear quotient is the asymptote and the remainder vanishes at infinity. In (x² + 3x + 1)/(x + 1) the division gives x + 2 with remainder -1, so the asymptote is y = x + 2. It only exists when the numerator degree is exactly one more than the denominator degree.
Quadratic function, f(x) = ax² + bx + c with a not equal to 0. The graph is a parabola, symmetric about the vertical line through the vertex. Here a = 1, b = -4 and c = 3; the parabola opens upward.
Exact result (algebra)
Linear function, f(x) = ax + b. The graph is a line: a is the slope (increasing if a is positive) and b is where the line crosses the y axis. Here a = 0.5 (increasing) and b = 1.
Exact result (algebra)
| x | f₁(x) | f₂(x) |
|---|---|---|
| -5 | 48 | -1.5 |
| -4 | 35 | -1 |
| -3 | 24 | -0.5 |
| -2 | 15 | 0 |
| -1 | 8 | 0.5 |
| 0 | 3 | 1 |
| 1 | 0 | 1.5 |
| 2 | -1 | 2 |
| 3 | 0 | 2.5 |
| 4 | 3 | 3 |
| 5 | 8 | 3.5 |