Two dice
- Input
- P(A)=1/6, P(B)=1/6
- Expected output
- P(A∩B)=1/36
Independent events.
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probability of two events
The union of two events is P(A) + P(B) − P(A∩B).
Independent events.
0.5 + 0.4 − 0.2.
Divide favorable outcomes by possible outcomes. Rolling a die, the chance of a 4 is 1 ÷ 6 ≈ 0.167 = 16.7%.
Events that cannot happen together: P(A∩B) = 0, so P(A∪B) = P(A) + P(B).
They are independent when P(A∩B) = P(A)·P(B); one does not change the other's probability.
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