0.00500 keeps all 3 figures
- Input
- 0.00500
- Expected output
- 5.00 × 10^-3
The decimal point makes both zeros significant, so the output keeps 3 figures and the decimal field also comes back as 0.00500.
significant figures scientific notation
Scientific notation is not only about shortening large numbers: it declares how many digits were actually measured. 1.2×10³ claims two reliable digits, 1.200×10³ claims four. This converter reads that declaration from what you type and returns the coefficient with the same precision.
The decimal point makes both zeros significant, so the output keeps 3 figures and the decimal field also comes back as 0.00500.
That is 4 figures declared in the coefficient; the exponent 3 does not enter the count, it only positions the decimal point.
With no decimal point the convention does not treat the zeros as measured, so 2 figures come out; with the trailing point, 36000. returns 3.6000×10⁴.
It is a way to write numbers as a × 10ⁿ, where the coefficient a is between 1 and 10 (in absolute value) and n is an integer (positive, negative or zero).
Yes. The converter counts the figures in the coefficient you wrote, not in the number after conversion, so 1.200e3 returns 1.200×10³. The exponent never changes the count: it only says which power of 10 multiplies the coefficient.
Because a trailing zero in an integer with no decimal point is ambiguous under the standard convention: there is no way to tell whether it was measured or is merely positional. Assuming 3 figures would be inventing precision. If your measurement has 3, write 36000. with the trailing point or enter the coefficient directly, as 3.60e4.
In multiplication and division the result carries the smallest figure count among the factors; in addition and subtraction the criterion is the least precise decimal place, not the figure count. Round only at the end, never at each intermediate step, so rounding error does not accumulate.
All calculations stay in your browser. No data is sent to any server.