10 kΩ at 50 ppm/K
- Input
- brown-black-black-red-brown-red
- Expected output
- 10k ±1% 50ppm/K
100 × 100 = 10,000 Ω. Over 50 K the drift is 10,000 × 50 × 10^-6 × 50 = 25 Ω.
6 band resistor color code
The sixth band is the odd one out. The first four give the resistance, the fifth tells you how far a part may start from that value, and the sixth tells you how much it moves when the temperature changes. Brown, black, black, red, brown, red is a 10 kΩ part, ±1%, at 50 ppm/K.
100 × 100 = 10,000 Ω. Over 50 K the drift is 10,000 × 50 × 10^-6 × 50 = 25 Ω.
Same value, brown sixth band: twice the coefficient, so 50 Ω of drift over 50 K.
220 × 10 = 2,200 Ω. Orange is 15 ppm/K: over 50 K the shift is 1.65 Ω, far below the ±22 Ω of tolerance.
100 × 1,000 = 100,000 Ω. Green is ±0.5% and blue is 10 ppm/K, which gives 50 Ω of drift over 50 K.
470 × 10 = 4,700 Ω. Violet is 5 ppm/K, and 4,700 × 5 × 10^-6 × 50 comes to about 1.2 Ω.
Start from the end opposite the tolerance band. The tolerance band is usually gold or silver (or visibly set apart from the rest with a wider gap), so it's always read last, and tells you which end to begin at.
It is the temperature coefficient, in ppm/K. It tells you how much the resistance changes for every kelvin of temperature change. It does not alter the nominal value you read from the other bands.
Multiply the value by the coefficient in ppm, by 10^-6 and by the temperature change. For 4.7 kΩ at 5 ppm/K and 40 K of warming: 4,700 × 5 × 10^-6 × 40 = 0.94 Ω.
Grey, at 1 ppm/K. At the other extreme sits black, at 250 ppm/K, which moves 250 times more per kelvin.
No. The first five bands read exactly as on a five-band part (three digits, multiplier, tolerance), and the sixth is simply added at the end.
This is a standard E24 value (typical tolerance ±5%).
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