Start from rest
- Input
- v₀ = 0, a = 2 m/s², t = 5 s
- Expected output
- v = 10 m/s, Δs = 25 m
Velocity from the first equation and displacement from the second.
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suvat calculator constant acceleration
Constant acceleration involves five quantities (displacement, initial velocity, final velocity, acceleration and time) and knowing three is enough to get the other two. The hard part is never the arithmetic, it is choosing the equation that does not ask for the missing value. The constant-acceleration screen makes that choice, says why and shows every substitution.
Velocity from the first equation and displacement from the second.
108 km/h ÷ 3.6 = 30 m/s; then t = (0 - 30)/(-5) and Torricelli for the displacement.
v² = 100 + 96 = 196; the negative root would need a negative time and is dropped.
100 km/h is 27.78 m/s; a = 27.78/10 and Δs = (0 + 27.78)·10/2.
It passes the point on the way out and on the way back.
With that deceleration the speed only falls; the problem is wrong or the sign of a is swapped.
In uniform motion the velocity does not change (zero acceleration) and position grows along a straight line on the s-t graph: S = S₀ + v·t. With constant acceleration the acceleration is non-zero, velocity changes linearly, v = v₀ + a·t, and the s-t graph is a parabola: S = S₀ + v₀·t + a·t²/2. Uniform motion is the special case with a = 0. A car at a steady 72 km/h covers 100 m in 5 s; one starting from rest with a = 2 m/s² covers 25 m in the same 5 s.
Three of the five quantities (displacement, u, v, a and t). With fewer there are infinitely many solutions; with more, the extra data act as a check and the calculator warns if one disagrees with the others.
The sign depends on the axis you chose. If the body moves in the negative direction (v < 0) and a is also negative, it speeds up. What defines braking is v and a having opposite signs, which makes the magnitude of the velocity shrink.
Yes, with a = 0. Then v = v₀ at every instant, Δs = v·t and the v-t graph is a horizontal line. The calculator handles it by itself: with a = 0 and Δs and v₀ given, the time comes from Δs/v₀.
Uniform motion
Constant acceleration
Free fall and vertical
Horizontal launch
Oblique launch
Average speed
Units
= 100 m
Leave blank what you want to find. Three values are enough for constant acceleration, two for uniform motion.
Δs = v·t
Δs = v·t
Δs = 20·5 = 100
Δs = 100 mThe slope of the curve at each point is the velocity at that instant.
Area under the curve (signed) = displacement Δs = 100 m.
Area under the curve = change in velocity Δv = 0 m/s.